Question

A ball released from certain height, falls under
the action of gravitational pull. The distance
travelled by ball after 10 seconds will be

a.100 m
b. 98 m
C. 49 m
d. 490 m
​

Answer 1

⭐find=⭐

distance??

⭐Given=⭐

time= 10 sec

acceleration of gravity = 9.8m/s^2

⭐solution ⭐

putting values in equation of motion

$\boxed{s = ut + \frac{1}{2} a{t}^{2} }$

s= (0 x 10 ) + 1/2 (9.8) (10^2)

s= 0 + 4.9 x 100

s= 490m

Distance = 490m

option d is correct✔✔

Answer 2

Answer:

time= 10 sec

acceleration of gravity = 9.8m/s^2

Explanation:

putting values in equation of motion

\boxed{s = ut + \frac{1}{2} a{t}^{2} }

s=ut+

2

1

at

2

s= (0 x 10 ) + 1/2 (9.8) (10^2)

s= 0 + 4.9 x 100

s= 490m

Distance = 490m

option d is correct

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