Question

A Ball released from height h touch the ground
t sec after t /2sec since dropping height
body
from the ground?


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Answer 1

Answer:

Let h

1

be the height from the body after release from the top position.

So, we know that, S=

2

gt

2

So, for t second of time, h=

2

gt

2

And for

2

t

second of time

h

1

=

2

g(t/2)

2

Taking ratio of h and h

1

,we find the distance travelled from top point.

h

1

h

=4

⇒h

1

=

4

h

Now from bottom total height will be: h−

4

h

=

4

3h

Explanation:

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