Physics, asked by adieegonnarock, 3 days ago

A ball released from top of a tower. The ratio of work done by force of gravity in first, second and third second of the motion of the ball is

Answers

Answered by kumkumnandwana78

2

Answer:

1: 3: 5: is your correct answer

Explanation:

S=ut+21gt2;here u=0,g=10ms−2

S=5t2

if t=1s;S=5.12;S=5

if t=2s;S=5.22−5.12;S=20−5;S=15

if t=3s;S=5.32−5.22;S=45−15;S=25

Hence, the ratio is 1:3:5

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