Question

. A ball rolling down a hill was displaced 19.6 m while uniformlyacceleration?accelerating from rest. If the final velocity was 5.0 m/s. what was the rate of
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Answer 1

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Answer 2

Answer:

A ball rolling down a hill was displaced 19.6 m

so,

h=19.6mh=19.6m

the final velocity was 5.00m/s

so, v=5m/sv=5m/s

Since, a ball rolling down a hill was displaced

so, we get

u=0m/su=0m/s

we can use kinematic equation formula

v^2-u^2=2ahv

2

−u

2

=2ah

Here ,

v is final velocity

u is initial velocity

a is acceleration

h is height from which ball is dropped

now, we can plug our values

5^2-0^2=2a(19.6)5

2

−0

2

=2a(19.6)

2a\left(19.6\right)=5^22a(19.6)=5

2

2a\left(19.6\right)=252a(19.6)=25

a=0.63776m/s^2a=0.63776m/s

2

................Answer

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