Question

a ball rolling rolling along the ground with velocity of 10 m/s and comes to rest at rest at 8s.Find it's acceleration.​

Answer 1

Answer:

The Initial velocity of the ball = 10 m/s

The final velocity of the ball = 0 m/s

The time taken = 8 s

Acceleration = ?

Using first equation of motion :

⇒ v = u + at

⇒ 0 = 10 + a×8

⇒ 10 + 8a = 0

⇒ 10 = -8a

⇒ a = -10/8

⇒ a = -5/4

⇒ a = -1.25 m/s²

Hence, the acceleration of the ball = -1.25 m/s².

Three equations of motion :

1. v = u + at
2. s = ut + ½at²
3. v² - u² = 2as

Some more information :

• Velocity is said to be the rate of change of displacement.
• Acceleration is said to be the rate of change of velocity.
• Velocity, Acceleration and Displacement are vector quantities.

Answer 2

Answer:

✡ Given ✡

$\leadsto$ A ball rolling along the ground with velocity of 10 m/s and comes to rest at 8 sec.

✡ To Find ✡

$\leadsto$ What it's acceleration.

✡ Formula Used ✡

✴ v = u + at ✴

where,

• v = final velocity
• u = initial velocity
• a = acceleration
• t = time taken

▶ According to the question by using formula we get,

$\implies$ 0 = 10 + (a) (8)

$\implies$ 0 = 10 + 8a

$\implies$ 10 + 8a = 0

$\implies$ 10 = - 8a

$\implies$ a = $\dfrac{-10}{8}$

$\implies$ a = $\dfrac{-5}{4}$

$\implies$ a = - 1.25 m/s²

$\therefore$ Hence, the acceleration of the ball is - 1.25 m/s².

Explanation:

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