Question

A ball rolls down a hill at a rate of 3.7 m/s2 . If it started from rest, in what distance would he reach a velocity of 12.00 m/s?

Answer 1

Answer :

›»› The final velocity of the body will be 300 m/s.

Given :

• Acceleration of a ball (a) = 3.7 m/s²
• Final velocity of a ball (v) = 12 m/s

To Calculate :

• Distance travelled by a ball (s) = ?

How to Calculate?

❒ Since, we are provided with the Acceleration and the final velocity of a ball, we can use the third equation of motion to find the distance travelled by the ball.

But according to the given information, body started from rest, i.e, the Initial velocity of the ball will be 0, although the Final velocity will have some value.

Here, we concluded that :

→ Initial velocity of the ball is 0 m/s.

Let's calculate the distance travelled by the ball...$.$

Calculation :

From third equation of motion

⇒ v² = u² + 2as

⇒ 12² = 0² + 2 * 3.7 * s

⇒ 144 = 0 + 2 * 3.7 * s

⇒ 144 = 0 + 7.4 * s

⇒ 144 = 7.4 * s

⇒ 144 = 7.4s

⇒ s = 19.45

║Hence, the distance travelled by the ball is 19.45 m.║

Answer 2

Given :-

☄ Acceleration, a = 3.7 m/s²

☄ initial velocity, u = 0m/s

☄ Final velocity, v = 12 m/s

To find :-

Distance travelled by the ball

Solution :-

using the equation of motion .i.e.,

➠ v² = u² + 2as

➠ 12² = 0² + (2)(3.7)(s)

➠ 144 = 0 + (2)(3.7)(s)

➠ 144 = 0 + (7.4)(s)

➠ 144 = 7.4s

➠ s = 19.45m

thus, the distance travelled by the ball is 19.45 m.

$\:$

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