Question

A ball rolls down a hill with a constant acceleration of
2.0

m
/
s
2
. If the ball starts from rest,

(a) what is its velocity and the end of
4.0

s
?

(b) How far did the ball move?

Answer 1

Answer:

Answer:8m/sec IS THE CORRECT ANSWER

Answer 2

Answer:

a) 8 m/$s^{2}$

b) 16 m

Explanation:

Using the formula,

1. v = u + a*t and  

2. x = u*t + $\frac{1}{2}$ a*$t^{2}$

Now, using first formula, we get:

v = u + a*t

v = 0 +2 * 4  ⇒  v = 8 m/$s^{2}$.

Then, using second formula, we get:

x = u*t + $\frac{1}{2}$ a*$t^{2}$

x = 0 * 4 + $\frac{1}{2}$ 2 * $(4)^{2}$  ⇒  x = 16 m.

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