Question

A ball rolls down a ramp for 15 seconds. if the initial velocity of the ball was 0.8m/sec what was the acceleration of the ball
​

Answer 1

Answer:

a

x

=

0.41

 

m/s

2

Explanation:

We're asked to find the (constant) acceleration of a ball as it rolls down a ramp, given its initial and final velocities, and the time interval.

To do this, we can use the equation

v

x

=

v

0

x

+

a

x

t

where

v

x

is the final velocity (

7

 

m/s

)

v

0

x

is the initial velocity (

0.8

 

m/s

)

a

x

is the constant acceleration (what we're trying to find)

t

is the time interval (

15

 

s

)

Plugging in known values, we have

7

 

m/s

 

=

0.8

 

m/s

 

+

a

x

(

15

l

s

)

a

x

=

7

l

m/s

−

0.8

l

m/s

15

l

s

=

0.41

l

m/s

2

−−−−−−−−−  

rounded to  

2

significant figures.