Question

A ball rolls off of a top of a stay away with horizontal velocity U metre per second if first r h metre high and emitter which the ball will just hit a age and step then what does the value of n.​

Answer 1

Answer:

The value of n is 2hu^2/gr2

Explanation:

According to the problem the ball has the velocity of Um/s

The height of each step is h m and width of each step is r meter

and by hitting the vertical distance traveled by the ball is nh and horizontal distance traveled is nr

Let T be the time of fall

Let the initial  vertical velocity =0

Therefore

nr=ut...(i)

nh=0+1/2gT^2......(ii)

from (i) and (ii)

n=2hu^2/gr2