Question

A ball slides off a horizontal table top 1.25 m high, with a velocity of 4 m/s. Find the horizontal distance from the edge of the table at which the ball strikes the ground.

Answer 1

Answer:

$1.25 = \frac{1}{2} (10)(t {}^{2} ) \: \: \: \: \: \: \: \: \: \: t = 0.5s$

$horizontal \: distance = 4 \times 0.5 = 2m$

Answer 2

Answer:

1.25 = \frac{1}{2} (10)(t {}^{2} ) \: \: \: \: \: \: \: \: \: \: t = 0.5s1.25=21(10)(t2)t=0.5s

horizontal \: distance = 4 \times 0.5 = 2mhorizontaldistance=4×0.5=2m