A ball starts from rest and covers 16m in 4sec what is the acceleration of the ball
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Initial velocity u = 0
Distance d = 16 m
Time t = 4 s
Let acceleration be 'a'.
Now, motion is uniformly accelerated.
So,
d = ut + ½ at²
So, 16 = 0 + ½ a×(4)²
So, 16 = 8a
So, a = 2 m/s²
Thus, the Acceleration is 2 m/s²
Distance d = 16 m
Time t = 4 s
Let acceleration be 'a'.
Now, motion is uniformly accelerated.
So,
d = ut + ½ at²
So, 16 = 0 + ½ a×(4)²
So, 16 = 8a
So, a = 2 m/s²
Thus, the Acceleration is 2 m/s²
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