Physics, asked by wadkark47, 18 days ago

A ball starts from rest on a horizontal floor and is given an acceleration of 2 m/s2. It hits the wall at a distance d from it. In the last second before it hits the wall, it covers a distance of 15 m. Find the distance d.​

Answers

Answered by kavitasingh1234
3

A ball starts from rest on a horizontal floor and is given an acceleration of 2 m/s2. It hits the wall at a distance d from it. In the last second before it hits the wall, it covers a distance of 15 m. Find the distance d.

Acceleration of the ball = 2 m / Sec²

Distance = d meter

Distance covered at the last second before it hits the wall = 15 m

________________________

So, 15 = 2/2 ( 2×n-¹ )

=> 15 = 2n-1

=> 2n = 16

=> n = 8 sec

_____________

Formula used :-

u= u+at

=2as

s= /2a

= 0+2×8

= 16 m / sec

Putting in third formula :

So , the distance covered by the ball is 64 meter .

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