Question

A ball strikes a bat with a velocity and gets rebounded with the same velocity. 1 What is the change of momentum in this process?

Answer 1

Answer:

Let the mass of the ball be = m

Initial velocity = u (let)

Therefore, initial momentum = p = mu

(as p = mv).

Now, final velocity after deflection = v (let) = u.

So, final momentum = p′ = mv

Now,

∆p = p′ - p

=> ∆p = mv - mu

=> ∆p = mu - mu (as v = u)

=> ∆p = 0. (Answer.)