a ball through in upward direction with velocity 20m/s find time taken by the ball to reach the ground
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Let us take the point of projection as the origin of coordinate system. Let the up direction be taken as positive.
The initial velocity of the body = + 20 m/s
Acceleration due to gravity a= - 10 m/s²
Let the time taken to return to the ground be t second
Since the objects return to the ground, the displacement s= 0 m
Using the relation; s = u × t + ½ a t².
Substituting various values
0 = 20 t - ½ × 10× t²; ==> 20 t - 5 t² = 0;
5 t² - 20 t = 0; ==> 5 t (t - 4) = 0; ==> t= 0 sec. or t = 4 sec.
The body would be at the ground at the beginning ie at t =0 and again at t = 4 s.
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