Question

A ball throw vertically afford with speed of 49m/s calculate
1.maximum height gain by the ball
2.total time taken by the ball with earth surface..
Give me Anwer fast with solution..

Answer 1

maximum height
$h = u { }^{2} \div 2g$
h=49×49/2×9.8
h=122.5
time taken
$t = 2u \div g$
t=2×49/9.8
t=10sec