Question

A ball, thrown by a boy, is caught by another boy in 2s. What is the maximum height attained by the ball?
O 10 m
O 5 m
O 20 m
O 7.5 m​

Answer 1

Answer:

h=ut_1/2gt2

h(0)_1/2×10×4

h/ 20m

Answer 2

Answer :

◈ Time of flight = 2s

We have to find maximum height attained by the ball$.$

For a body thrown vertically upward

Time of flight = 2u/g

Max. height = u²/2g

ATQ :- Time of flight is 2s.

Therefore,

➝ 2 = 2u/g

➝ u = g

➝ u = 10m/s

Max. height attained by ball :-

➝ H = u²/2g

➝ H = 10²/2×10

➝ H = 5m