Question

A ball thrown by a player reaches another player reaches another player in 2s. What is the maximum height

Answer 1

the distance between the two bodies be d

speed between two bodies be s

time taken = 2 sec

distance = speed × time

d= s×2sec

d=2s

Answer 2

Answer:

H=5m

Explanation:

T=2s

g=10

so,T=2= 2u sinϑ/g

2g= 2 u sinϑ

20=2u sin ϑ

u sinϑ= 20/2

u sinϑ= 10-----(1)

H=(u sinϑ)²/2g

from equation 1

=10²/2×10

H= 100/20

=5m