a ball thrown by a player reaches other player in 2 seconds. find height attained by the ball above point of projection
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If the total flying time is 2s, time taken to reach the maximum height is 1s,
Applying v=u+at
u = 0-10x1
u=10ms^-1
Applying v^2 = u^2 + 2as
s = (0 - 10)2x10 [Final velocity becomes zero]
s = - 0.5m [negative sign represents the direction - outwards the floor]
Applying v=u+at
u = 0-10x1
u=10ms^-1
Applying v^2 = u^2 + 2as
s = (0 - 10)2x10 [Final velocity becomes zero]
s = - 0.5m [negative sign represents the direction - outwards the floor]
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