Question

A ball thrown by one player reaches the other in 2 sec The maximum height attained by the ball above the point of projection will be about.

Answer 1

Answer:

Explanation:

T = 2uSinθ/g

2 = uSinθ/g

Squaring on both sides

4 = u²Sin²θ/g²

u²Sin²θ = 4g² ———(1)

H = u²Sin²θ/(2g)

From equation (1)

H = 4g²/(2g)

H = 2g

H = 2 × 9.8

H = 19.6m

now add players height ie 1.5

then answer is 21.1 mts

Answer 2

Answer:

మీకు ఏవైనా ప్రశ్నలు ఉన్నాయో లేదో ఎప్పుడైనా లింక్‌ను పొందిన మొదటిది, కాని జి జీ సరే నేను మీకు డబ్బును ఇమెయిల్‌లో పొందుతాను మరియు మరొకటి ఇన్‌స్టాగ్రామ్‌లో ఉంది

Explanation:

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