A ball thrown in air attains 100m height and cover horizontal distance of 150m on ground . draw the path of the ball .name the curve
Answers
Given : A ball thrown in air attains 100m height and cover horizontal distance of 150m
To Find : Speed and angle of the ball thrown
Solution:
Let say after T min ball reaches it max height
Velocity = V angle = α
Vsinα = gT
=> T = Vsinα/g
V² = 2 g(100)
=> V²sin²α = 200g Eq1
Vcosα * 2T = 150
=> Vcosα * 2Vsinα/g = 150
=> V² SinαCosα = 75g Eq2
Eq1/Eq2
=> tanα = 8/3
=> α =69.444°
cosα = 1/√(1 + (8/3)² = 3/√73
Sin α = 8/√73
Sin ²α = 64/ 73
V²sin²α = 200g
=> V² = 200g * 73/64
=> V ≈ 47.5 m/s
at angle 69.444°
Path will be parabola
Parabolic equation is (x-75)² = -56.25 (y-100)
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