Physics, asked by jhavikashkumar903, 10 months ago

A ball thrown in air follows a path by y=x/√3-3g/8x^2m qhere x axis is taken along the horizontal and y axis along the verticle the maximum displacement of the ball along x direction for which displacement along y is zero equal to

Answers

Answered by jit71
1

Explanation:

8x^2m qhere x axis is taken along the horizontal and y axis along the verticle the maximum displacement of the ball along x direction for which displacement along y is zero equal to

Answered by jivinverma2004
5

Answer:

y=0                        (given)

therefore,

              0 =x/root3  -3gx^2/8

               0=(8)x -3(root3)gx^2/8root3

               putting the value of g=10m/s in above equation

              0=8x -30root3x^2

              30root3x^2 =8x          (x cancels each other)

              30root3x =8

              x= 8/30root3

              x=4/15root3              ANSWER

                 PLS MARK THE BRAINLIEST                                              

Explanation:

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