Question

A ball thrown in the upward direction with speed of 40m/s find i) the maximum height achieved by the ball ii) the time at which ball will reach at maximum height​

Answer 1

Answer:

A)maximum Height  

h=  

2g

u  

2

sin  

2

θ

​

 

h=  

2×10

40  

2

sin  

2

60

​

 

h=60m

B) Horizontal Range  

X=  

g

u  

2

sin2θ

​

 

X=  

10

40  

2

sin2×60

​

 

∴=80  

3

​

m