a ball thrown in vertically upward direction rise up to a height (h) and comes back to the position of its shorts . calculate the total distance travelled by the ball
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A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate
(i) The maximum height to which it rises.
(ii) The total time it takes to return to the surface of the earth.
October 15, 2019avatar
Akash Sabiya
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ANSWER
Given Initial velocity of ball, u=49 m/s
Let the maximum height reached and time taken to reach that height be H and t respectively.
Assumption: g=9.8 m/s
2
holds true (maximum height reached is small compared to the radius of earth)
Velocity of the ball at maximum height is zero, v=0
v
2
−u
2
=2aH
0−(49)
2
=2×(−9.8)×H
⟹H=122.5 m
v=u+at
0=49−9.8t
⟹t=5 s
∴ Total time taken by ball to return to the surface, T=2t=10 s
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