Question

A ball thrown up from the ground reaches a
maximum height of 20 m. (g = 10 m/s2) Find :
(a) its initial velocity
(b) the time taken to reach the highest point
(c) its velocity just before hitting the ground
(d) its displacement between 0.5 s and 2.5 s
(e) the time at which it is 15 m above the ground.​

Answer 1

Answer:

As we know

u=?

h=20

g=-10

v=0

From equation v^2-u^2=2gH

-u^2=-400

u=20

From v=u+at

-20=-10t

T=2s

Velocity just before hitting ground will be 20