Question

A ball thrown up is caught back by the thrower after 6 sec. Calculate
(i) the velocity with which the ball was thrown up, (ii) The maximum
height attained by the ball and (iii) The distance of the ball below the
highest point after 2 sec. Take, g= 10m/s^2

Answer 1

(i)v=velocity=29.4m/s
(ii)h=height=144.06m
(iii)distance at 2sec is 19.4m

Answer 2

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