Physics, asked by sohamdatta117, 1 year ago

A ball thrown up is caught by the thrower after 4 seconds after start. the height to which the ball has risen is

Answers

Answered by YadavShashi
4
v = u + at
0 = u + 10*4
u = - 40

s = ut + 1/2at^2
= 40* 4 + 1/2 *10*16
= -160 + 80
= -80
It will be 80m
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