A ball thrown up is caught by the thrower after 4 seconds after start. the height to which the ball has risen is
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v = u + at
0 = u + 10*4
u = - 40
s = ut + 1/2at^2
= 40* 4 + 1/2 *10*16
= -160 + 80
= -80
It will be 80m
0 = u + 10*4
u = - 40
s = ut + 1/2at^2
= 40* 4 + 1/2 *10*16
= -160 + 80
= -80
It will be 80m
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