Question

A ball thrown up to height of 5 m reaches to starting point in 2 sec. What is the displacement of ball? *

Answer 1

Answer: 0 m

Explaination :

as it comes to its original position, its shortest distance covered is zero

Answer 2

Answer:

Displacement is 29.6

Explanation:

V = 5m

t = 2 sec

a = - g = - 9.8 m/ s^2

x = ?

V = Final velocity

t. = time in second

a = acceleration

x = displacement

v. = initial velocity

V = v. + at

5 = v. + ( - 9.8) 2

5 = v. - 19.6

5+ 19.6 = v.

24.6= v.

X = v. t + 1/2 at^2

X = 24.6 x 2 + 1/2 ( -9.8) 2^2

X = 49.2 + 1/2 ( -9.8) 4

X = 49.2 + 4/2 ( -9.8)

X = 49.2 + 2(-9.8)

X= 49.2 - 19.6

X= 29.6