Question

A ball thrown up vertically returns to the thrower after 5 seconds. Find the velocity with which it was thrown up.(acceleration due to gravity= 10m/ sq sec) *
options are :-
1)20m/s
2)22.5m/s
3)25m/s
4)29.4m/s

Answer 1

Answer:

v = 0

u = x m/s

t = 5 sec as the ball go to height h and come back 5/2 = 2.5 sec

a= 10m/s^2

finding the initial velocity

v= u + at

v = 0

0= x + 10*2.5;

x= 0+25

x= 25m/s

Explanation:

hope this will help you