Question

A ball thrown up vertically returns to the thrower after 6 seconds. Find the velocity with which it was thrown up.


29 m/s

29.8 m/s

29.2 m/s

29.4 m/s

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Answer 1

Answer:

(a) Time of ascent is equal to the time of descent. The ball takes a total of 6 s for its upward and downward journey. Hence, it has taken 3 s to attain the maximum height. Hence, the ball was thrown upwards with a velocity of 29.4 m s−1

Explanation:

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Answer 2

Answer:

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Since,

Ball is thrown vertically then, we get

• Final Velocity (v) →0m/s
• Acceleration due to gravity→ -10m/s²
• Time→6 seconds

To find Initial velocity (u).

The ball returns to the ground after 6 seconds.

Thus the time taken by the ball to reach to the maximum height (h) is 3 seconds i.e t=3 s

Let the velocity with which it is thrown up be u

From Formula:

v=u+at

Putting all the values:

=>0m/s=u+(-10m/s²)×3 seconds

=>u=30m/s

Hence the velocity which it was thrown up was 30m/s

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