A ball thrown up vertically returns to the thrower after 6 second find the velocity with which it was thrown up
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The solution is given below....Hope it helps! g= -9.8
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_/\_Hello mate__here is your answer--
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The ball takes a total of 6 s for its upward and downward journey. (Time of ascent is equal to the time of descent.)
Hence, it has taken 3 s to reach at the maximum height.
v = 0 m/s
g = −9.8 ms−2
Using equation of motion,
v = u + at
⇒0 = u + (−9.8 × 3)
⇒ u = 9.8 × 3 = 29.4 m/s
Hence, the ball was thrown upwards with a velocity of 29.4 m/s.
I hope, this will help you.☺
Thank you______❤
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