Question

A ball thrown up vertically returns to the thrower after 6 s. Find. the maximum height it reaches.

Answer 1

hi, there !!!

6 = 2u / g

60 = 2u { g = 10 }


u = 30

maximum height = u² / 2g


30 × 30 / 2 × 10

=> 45 m


hope it helps you !!;



thanks !!

Ranjan kumar

Answer 2

Here is your answer...
6=2u/g

g=10
60=2u
u=30

Maximum height =u2/2g
=30×30/2×10
➡45m

Hope it's help you✌✌✌✌✌
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