A ball thrown up vertically returns to the thrower after 6s. Find the velocity with which it was thrown up
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Class 9
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Answered by
3
Initial velocity =u
Final velocity = 0
time =3 sec
acceleration due to gravity = -10 m/s ( retarding acceleration )
v=u+at
0= u+(-10)×3
u= 30
u= 30 m/s
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Final velocity = 0
time =3 sec
acceleration due to gravity = -10 m/s ( retarding acceleration )
v=u+at
0= u+(-10)×3
u= 30
u= 30 m/s
Hope it helps....
Mark it as Brainliest....
ansh2014chauhan:
sorry it's wrong
what is the correct answer then..??
30 m per second
Thanks... I found where I was wrong.....
Thank you very much.... BTW I know the answer but just I want to confirm....
Hmmm
hmm
Answered by
0
Time to reach Maximum height,
t = 6/2 = 3 s.
v = 0 (at the maximum height)
a = – 9.8 m s–²
Since the ball is thrown upwards, the acceleration is negative.
(i) Velocity
Using, v = u + at, we get
0 = u – 9.8 × 3
or, u = 29.4 ms–¹
Thus, the velocity with which it was thrown up = 29.4ms–¹
Hope it helps you Ansh !
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