Question

A ball thrown up vertically returns to the thrower in 4s . Find the initial velocity of the ball, the maximum height and its position after 3 sec.​

Answer 1

Answer:

time of flight is given to us=4 second

t=2 u sin(theta)/g

here projection is vertical theta =90°

to find: H max and u

Explanation:

use the formula :

u=t g/2

u=(4*10)/2

u=20 m/s

next H max=u²/2 g

we will get H max=(20*20)/(2*10)

H max=  20 m

i hope this gonna help you

Answer 2

Answer:

20 m is your answer mate ok