A ball thrown up vertically upwards reaches a certain height in 6 seconds. calculate the velocity with which it is thrown up, if g= 10m/s2
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A ball thrown up vertically upwards reaches a certain height in 6 seconds.
We have to find the velocity of the ball with which ball is thrown up.
From above data we have; height (h) is 6 m, final velocity (v) is 0 m/s [ at highest point, velocity = 0 ] and acceleration due to gravity (a) is -10 m/s [ as it is against the motion ]
First equation of motion:
v = u + at
Second equation of motion:
s = ut + 1/2 at²
Third equation of motion:
v² - u² = 2as
As we have value of v, a and s. So, using the Third Equation Of Motion i.e. v² - u² = 2as
Substitute the known values in the above formula,
→ (0)² - u² = 2(-10)(6)
→ 0 - u² = -120
→ u² = 120
→ u = 10.95
→ u = 11 (approx.)
Therefore, the initial velocity of the ball is 11 m/s.
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