Question

a ball thrown up with 10 m/s will return to ground after​

Answer 1

Answer:

• S = ut + 1/2at^2
• 0 = 10 × t - 1/2 × 10 × t^2
• 10t = 5t^2
• 5t = 10
• t = 2

that's the answer mate... ;)

Answer 2

Hey Dear,

◆ Answer -

Stone will reach ground after 4 s.

◆ Explaination -

Time required for ball to reach max height,

v = ut - (1/2)gt^2

0 = 10×t - (1/2) × 9.8 × t^2

10t = 4.9t^2

t = 2 s

Time required for ball to reach ground will be same as to reach top.

Therefore, stone will reach ground after 2×2 = 4 s.

Hope this helped you. Thanks for asking..