A ball thrown upward from the top of tower with speed V reaches the ground in T1 second. If this ball is thrown downward from the top of the same tower with speed V it reaches the ground in T2 second. In what time the ball shall reach the ground if it is allowed to fall freely under gravity from top of the tower?
(a) T1+T2/2
(b) T2-T1/2
(c) √T1T2
(d) T1+T2
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Answered by
1
Answer:
D) T1 + T2
Explanation:
T1 ≠ T2 but V1 = V2
therefore we can say
V1 ≠ V2 but T1 = T2
the ball travels with different speed but at same time!
Answered by
0
Answer:
this is the correct answer OK
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