a ball thrown upward with a speed of 100 M per second show that the ball hits the ground with same speed after returning from the highest point .g= 10 M per second square
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u=u m/s
g= -10 m/s^2
h= 100 M
v=0 m/sdat highest point speed is zero)
formula: v^2=u^2 - 2gh
0=u^2 - 2000
u^2=2000
u=20√5m/s
now, ball ruterning to the ground
so, u'=0 m/s
h= 100M
g =10m/s^2
v'= x m/s
formula: v^2=u^2 +2gh
x^2=o + 2000
x = 20√5m/s
here, u=x
hence proved
I hope.... It is helpful
g= -10 m/s^2
h= 100 M
v=0 m/sdat highest point speed is zero)
formula: v^2=u^2 - 2gh
0=u^2 - 2000
u^2=2000
u=20√5m/s
now, ball ruterning to the ground
so, u'=0 m/s
h= 100M
g =10m/s^2
v'= x m/s
formula: v^2=u^2 +2gh
x^2=o + 2000
x = 20√5m/s
here, u=x
hence proved
I hope.... It is helpful
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