Question

a ball thrown upwards and returns to the thrower after 12 sec calculate:
1) the velocity with which it was thrown up
2)the maximum height it reaches
3)it's position after 8 sec​

Answer 1

Answer:

options A is a correct answer this question

Answer 2

The ball returns to the ground after 12 seconds

maximum height = 6 seconds

Let the velocity which the ball thrown be 'x'

a)

the velocity which the ball was thrown up..

velocity (v)

v = x + at

0 = x + (-10) × 6

= 60 m/s

b)

The maximum height reached by the ball..

height = xt + 1/2 at2 ( 2- square )

h = 60× 6+ 1/2 (-10) ×6 ( square)

c)