Question

A ball thrown upwards reaches a height of 10 m. It's initial velocity is.​

Answer 1

Explanation:

AVERAGE VELOCITY =

INITIAL VELOCITY + FINAL VELOCITY ÷ 2

→ INITIAL VELOCITY - 0

→ FINAL VELOCITY - 10 M

→SO , THAT - 10 M + 0

- 10 M

- 10M ÷ 2

- 5 M/ S^2

Answer 2

Given :

⇒ A ball is thrown vertically upward.

⇒ Max. height attained by ball = 10m

To Find :

➳ Initial velocity of ball.

Solution :

⟶ Acc. due to gravity continuously acts in the downward throughout the motion.

⟶ For a body thrown vertically upward, g is taken negative.

⟶ Final velocity of ball at maxium height = zero.

$\implies\tt\:v^2-u^2=2gH\\ \\ \implies\tt\:(0)^2-u^2=2(-g)H\\ \\ \implies\tt\:u^2=2gH\\ \\ \implies\tt\:u=\sqrt{2gH}\\ \\ \implies\tt\:u=\sqrt{2\times 10\times 10}\\ \\ \implies\tt\:u=\sqrt{200}\\ \\ \implies\underline{\boxed{\bf{u=10\sqrt{2}\:ms^{-1}}}}$