A ball thrown upwards return to thrower after 6 seconds:
(a)Find the distance travelled during whole journey?
(b)Find distance travelled after 4 seconds?
(c)What is velocity after 2 seconds?
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The ball takes a total of 6 s for its upward and downward journey. Hence, it has taken 3 s to attain the maximum height. Hence, the ball was thrown upwards with a velocity of 29.4 m s−1. ... This means that the ball is 39.2 m (44.1 m − 4.9 m) above the ground after 4 seconds
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