Question

A ball thrown vertically returns to the thrower after 8 sec what is its velocity with which it was thrown up

Answer 1

t = 4s

u = ?

v = 0 m/s

a = -10 m/s

v=u+at

0 = u + (-40)

= u = 40 m/s

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Answer 2

given,

total time = 8s

time taken by ball to go up,t =8/2=4s

a=-10m/s²

v=0m/s

now,

v= u + at

0= u -10×4

40m/s =u

therefore velocity at which ball is thrown up is 40m/s