Question

a ball thrown vertically returns to the thrower after 8s . find (c) it's position after 5 sec​

Answer 1

Explanation:

Hope it will help you..........

Answer 2

Explanation:

After 3 seconds, it starts to fall down

Let the distance by which it fall in 1s be x

x = 0 + 1/2 at `2 and. where `t = 1s

x = 1/2 × 10 × (1)^2 = 5 m

Therefore, it's height above the ground, h` = 45 - 5 = 40m

Hence after 4s, the ball is at height of 40m above the ground

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