Question

A ball thrown vertically thorough upward with an initial velocity of 40cm per second. find the following maximum height total distance convert net displacement​

Answer 1

Explanation:

Ball is thrown vertically upward with velocity 40m/s . at highest point, velocity of ball equals zero.

use formula, v = u + at,

here, v = 0, u = 40 m/s and a = -g [ negative sign shows that acceleration due to gravity acts downward direction.]

so, 0 = 40 - 10t

t = 4sec

and maximum height reached by ball = u²/2g

= (40)²/20 = 80m

hence, after 4sec ball reaches highest position.

then, ball starts to fall downward direction.

so, initial velocity in this case , u= 0

after 2 sec ball falls , S distance below from highest point.

use formula, S = ut + 1/2at²

S = 0.t + 1/2(-g) × 2² = -20m

hence,first 4sec ball reaches 80m heigh from the ground then, falls 20m below from the top point in next 2 sec .so, displacement in 6sec = 80m - 20m = 60m