Question

A ball thrown vertically up reaches a maximum height of 5m. With what velocity was
it thrown up?​

Answer 1

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The equation is given as v^2 −u^2 =2as.

where,

v = final velocity,  

u = initial velocity,  

a = acceleration due to gravity, 10m/s^2 ,  

s = h = height traveled.

Therefore, we can find u with the above info. In this case, v = 0 at the top of the path.

0−u^2

=2×10×5=10m/s.

Hence, the initial velocity of the ball was 10 m/s.

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