Question

A ball thrown vertically upward reaches a maximum height of 50m above the level of projection. calculate the, Time taken to reach the maximum height, The speed of throw. {Take acceleration due to gravity (g)=10m/s}

Answer 1

Answer:

10m/s

Explanation:

The equation is given as v2−u2=2as.

where,

v = final velocity, 

u = initial velocity, 

a = acceleration due to gravity, 10m/s2, 

s = h = height traveled.

Therefore, we can find u with above info. In this case, v = 0 at the top of the path.

0−u2=2×10×5=10m/s.

Hence, the initial velocity of the ball was 10 m/s.

Answer 2

${\huge{\bold{\blue{\underline{♡AnSwEr-♡}}}}}$

The equation is given as v2−u2=2as.

where,

v = final velocity, 

u = initial velocity,

a = acceleration due to gravity, 10m/s2, 

s = h = height traveled.

Therefore, we can find u with above info.

In this

case, v = 0 at the top of the path.

0- u^2 = 2×10×50

-u^2 = 1000

= 31.6227766017

u = - 31.63m/s (approx)