a ball thrown vertically upward reaches ground 4sec determine the total distance converd by ball assuming g=10m/sq sec
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Explanation:
it takes 4 sec to reach the ground
so it will take 2 sec to reach Max height..
v = u+at
(at Max height velocity is 0)
0 = u + (-10) (2)
u = 20 m/s
S = ut+1/2 at^2
= 20 (4) +1/2 (+10)(16)
= 80 + 80
= 160m
Also displacement is 0 as the ball return in its initial position..
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