A ball thrown vertically upward return back studio thrower in 4 seconds total distance covered by the ball is take g is equal to 10 metre per second square
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Answered by
1
Answer:
initial velocity - 20m
Explanation:
s=ut+1/2 at^2
= u×4+1/2 (-g)4^2
= 4u - 10×8
= 4 u- 80
s = u- 20m
Answered by
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is the distance covered by the ball.
Explanation:
Considering the half distance of the motion of the body when it is thrown from the ground till it is at the top height at rest before returning down the motion.
Given:
- initial velocity,
- final velocity,
- time taken,
- acceleration due to gravity,
Using equation of motion:
Now,
Therefore total distance on returning down from top will be:
TOPIC: equation of motion under gravity
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