Question

A ball thrown vertically upward return back studio thrower in 4 seconds total distance covered by the ball is

take g = 10 m/s^2​

Answer 1

Given :

A ball is thrown vertically upward returns back in 4 seconds.

To Find :

Total distance covered by the ball.

Solution :

❖ For a body thrown vertically upward, g is taken negative.

• First of all we need to find initial velocity of ball with which ball is thrown vertically upward$.$

For a body thrown vertically upward at a speed of u, total time of flight is given by

• T = 2u/g

» T denotes time of flight

» u denotes initial velocity

» g denotes acceleration

By substituting the given values;

➙ T = 2u/g

➙ 4 = 2u/10

➙ u = 40/2

➙ u = 20 m/s

★ Max. height attained by the ball :

➙ v² - u² = 2gH

➙ 0² - 20² = 2(-10)H

➙ 400 = 20H

➙ H = 400/20

➙ H = 20 m

Hence total distance covered by the ball will be 40m.

Answer 2

Given :

A ball is thrown vertically upward returns back in 4 seconds.

To Find :

Total distance covered by the ball.

Solution :

❖ For a body thrown vertically upward, g is taken negative.

First of all we need to find initial velocity of ball with which ball is thrown vertically upward$.$

For a body thrown vertically upward at a speed of u, total time of flight is given by

T = 2u/g

» T denotes time of flight

» u denotes initial velocity

» g denotes acceleration

By substituting the given values;

➙ T = 2u/g

➙ 4 = 2u/10

➙ u = 40/2

➙ u = 20 m/s

★ Max. height attained by the ball :

➙ v² - u² = 2gH

➙ 0² - 20² = 2(-10)H

➙ 400 = 20H

➙ H = 400/20

➙ H = 20 m

Hence total distance covered by the ball will be 40m.