Physics, asked by happy666, 1 year ago

a ball thrown vertically upward rises upto a height of 50 m , then it returns back to the initial position on calculate
(1) the total distance covered by ball
(2) the displacement of the ball​

Answers

Answered by JawaabDe
3

Answer:

Hey there,

Your Answer is

Explanation:

Total distance= 50+50=100

Displacement=50-50=0


happy666: that is not correct i think
JawaabDe: wait let me check
happy666: thanks bro
happy666: :b
JawaabDe: yep bro it's correct
JawaabDe: check if you want
happy666: thank you again
JawaabDe: never mind
happy666: now i am going to do holiday homework
JawaabDe: sure,All the best
Answered by hemakumar0116
0

Answer:  Total Distance : 50 + 50 = 100

                Displacement : 50 - 50 = 0

Explanation: Given : a ball thrown vertically upward rises upto a height of 50 m , then it returns back to the initial position

To Find : calculate

(1) the total distance covered by ball

(2) the displacement of the ball​

Solution : Total distance = 50 + 50 = 100

Displacement = 50 - 50 = 0

The total distance covered will be 100m. The distance between the beginning point and the height is +50m, while the distance between the height and the thrower is -50m. The magnitude cancels since the directions of both motions are opposite. As a result, the net displacement will be zero.

#SPJ2

Similar questions