a ball thrown vertically upward with a speed of 19.6 from the top of the tower returns to the earth in 6s find the height of the tower
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Takng vertical downwards motion of the ball frm point of projection up to ground, we have
u = -19.6 m/ sec
a = 9.8 m / sec square
t = 6 sec..
s = ut + 1/2 at square
s = - 19.6 * 6 + 1/2 * 9.8 * 6 * 6
s = 58.8 m ans..
HOPE U GET IT...
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